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The first, [:], is creating a slice (normally often used for getting just part of a list), which happens to contain the entire list, and thus is effectively a copy of the list I can not find tge list of account passwords tgat i saved in google account The second, list(), is using the actual list type constructor to create a new list which has contents equal to the first list.

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Given a dataframe, i want to groupby the first column and get second column as lists in rows, so that a dataframe like See flatten an irregular (arbitrarily nested) list of lists for solutions that. A b a 1 a 2 b 5 b 5 b 4 c 6 becomes a [1,2] b [5,5,4] c [6] how do i do this?

Don't use quotes on the command line 1 don't use type=list, as it will return a list of lists this happens because under the hood argparse uses the value of type to coerce each individual given argument you your chosen type, not the aggregate of all arguments

You can use type=int (or whatever) to get a list of ints (or whatever) A list of lists would essentially represent a tree structure, where each branch would constitute the same type as its parent, and its leaf nodes would represent values. In c# if i have a list of type bool What is the fastest way to determine if the list contains a true value

I don’t need to know how many or where the true value is I just need to know if one e. Model status certified —models are expected to work with chromeos flex Minor issues expected —models are likely to support at least basic functionality, but are still being worked on by our team

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You might run into minor issues

Is the a short syntax for joining a list of lists into a single list ( or iterator) in python For example i have a list as follows and i want to iterate over a,b and c. If your list of lists comes from a nested list comprehension, the problem can be solved more simply/directly by fixing the comprehension Please see how can i get a flat result from a list comprehension instead of a nested list?

The most popular solutions here generally only flatten one level of the nested list

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A brunette with a B-cup named Nikki Lee: Porn researcher claims to have